![]() Look up a textbook on C/C++ for more details. You could also use create a sufficiently large char buffer and use sprintf() from stdio.h to build a string made up of integers and strings. ![]() Lcd.print(String(number) + String(" plus ") + String(number) + String(" equals ") + String(result)) lcd.print(String("1234 ") + String(number)) In order to print something that contains both strings and integers, the most straightforward way is to convert each piece to an Arduino string and then concatenate them, using the + operator like you did earlier. 3 Answers Sorted by: 3 Do something like this: Start with your string and integer: String string 'PI is equal to ' int integer 3.1416 Then put this in your loop: Serial.print (string) //string here Serial.print (integer) //int here Serial.println () //change line Serial.print () doesn't change line. 2), thus making the pointer point to the 3rd character in the string and thus making lcd.print() display "34 ". So when you tried lcd.print("1234 " + number) and got "34 ", what most likely happened is that you advanced the pointer, pointing to the first character of "1234 "(i.e. In Arduino, if you have a std::string: serial-println-a-stdstring.cpp Copy to clipboard Download std::string str 'test' you can’t directly print it trying to do so leads to the following error messages: serial-println-a-stdstring.txt Copy to clipboard Download src/main. C strings are basically stored as pointers to the first character of the string. Using the + operator for concatenation is not native to C strings. I love that the Streaming library brings back the familiar syntax Serial << x through some template and macro magic. Yes int anInt 123 Serial.print ('Number ') Serial.print (anInt) Serial.println (' on the screen') Or use the sprintf () sledgehammer char buffer 30 int anInt 123 sprintf (buffer, 'Number d on the screen', anInt) Serial. In Arduino, you have to write a function call: Serial.print (x). The lcd.print() method takes a string or a number as an argument, but not both at once. Peter UKHeliBob April 8, 2017, 11:58am 2 Is it possible.
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